Given an array of ones and zeroes, convert the equivalent binary value to an integer.
Eg: [0, 0, 0, 1] is treated as 0001 which is the binary representation of 1.
Examples:
Testing: [0, 0, 0, 1] ==> 1
Testing: [0, 0, 1, 0] ==> 2
Testing: [0, 1, 0, 1] ==> 5
Testing: [1, 0, 0, 1] ==> 9
Testing: [0, 0, 1, 0] ==> 2
Testing: [0, 1, 1, 0] ==> 6
Testing: [1, 1, 1, 1] ==> 15
Testing: [1, 0, 1, 1] ==> 11
The link problem is here.
Solution:
#include <stddef.h>
unsigned binary_array_to_numbers(const unsigned *bits, size_t count)
{
unsigned numbers=0;
for(size_t i = 0; i < count; i++)
{
numbers += (bits[i] * pow(2,count-i-1));
}
return numbers;
}